6x^2+96x-264=0

Solution for 6x^2+96x-264=0 equation:

6x^2+96x-264=0

a = 6; b = 96; c = -264;
Δ = b2-4ac
Δ = 962-4·6·(-264)
Δ = 15552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15552}=\sqrt{5184*3}=\sqrt{5184}*\sqrt{3}=72\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-72\sqrt{3}}{2*6}=\frac{-96-72\sqrt{3}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+72\sqrt{3}}{2*6}=\frac{-96+72\sqrt{3}}{12}
$